# Intensity with mirrors

## Homework Statement

The EPM has finally crossed the fine line between party tricks and felonies
with the genocide of the pigmy marmoset. You are now determined to make him '
pay the price. You fashion a makeshift sherical mirror/laster beam our of a
roll of aluminum foil and a stick of bubblegum. Considering the power radiated
from the sun lands on earth with a maximum flux of almost a kilowatt per square
meter:

How large should the surface of the mirror be, if you are to deliver over a
megawatt per square meter over a 1 square centimeter monkey-butt surface?

I = P / A

## The Attempt at a Solution

I have tried this several times but I don't see the link between everything. I obviously have to use I = P / A and solve for A(mirror)

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Just to clarify, this is a mirror and not a lens...right?

correct.......

The question as i am reading isnt very clear. You would have to have a parabolic mirror to focus the light...so it would depend...unless im missing something

it's a spherical mirror...specifically a concave sphere.......

I know i have to use intensity but i don't know how i can relate the suns intensity to that of the mirror ; and / or power

Well, it would depend on the focal length of the mirror and the distance between obects

does the problem want a numerical answer, or an equation as a function of focal length and distance?

You have as much information as I do. It is all stated above. It wants to know how much area the mirror must have. hence i find the Intensity possibly very useful, since I = P / A .... but how can P be related from the sun to the mirror

Well, a mirror of size A=1000m^2 would obviously give you that amount of energy...but im not sure about other parameters and how they would affect...sorry