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Interceptor rocket?

  1. Nov 12, 2011 #1
    1. The problem statement, all variables and given/known data
    A 5000kg interceptor rocket is launched at an angle of 44.7 degrees. The thrust of the rocket motor is 140,700N
    a) Find an equation y(x) that describes the rocket's trajectory
    b) What shape is the trajectory?
    c) At what elevation does the rocket reach the speed of sound, 330m/s?

    2. Relevant equations
    kinematic equations
    Newton's laws


    3. The attempt at a solution
    The problem sheet hint tells me that the angle is not 44.7 degrees. So is it right that it should be 45.3 degrees then? Furthermore, speed initial is 0m/s correct?
     
  2. jcsd
  3. Nov 12, 2011 #2

    Delphi51

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    The angle will vary. The force of gravity will reduce the angle. It will be a curved trajectory with the angle continuously changing. Yes, it appears that the initial velocity is zero.

    Write the equations for vertical and horizontal motion to find out what happens. Looks interesting!
     
  4. Nov 12, 2011 #3
    I don't see how to start off a then because I get something over the initial velocity squared, which is zero. As a result, it should not be defined. Any hints?
     
  5. Nov 12, 2011 #4

    Delphi51

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    Oops, sorry, I shouldn't have commented. I don't know how to solve it. Quite a little set of differential equations involved! I can find the answers using a computer simulation but I've lost the ability to do varying acceleration problems via calculus.

    Funny, according to my little spreadsheet model, it doesn't get far off the ground.
    The component of the thrust in the vertical direction is very soon overcome by gravity and the rocket loses angle very quickly.
    rocket.jpg
     
    Last edited: Nov 12, 2011
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