Let n be a positive integer and suppose [tex]f[/tex] is continuous on [tex][0,1][/tex] and [tex]f(0) = f(1)[/tex]. Prove that the graph of [tex]f[/tex] has a horizontal chord of length [tex]1/n[/tex]. In other words, prove there exists [tex]x \in [0,(n - 1)/n][/tex] such that [tex]f(x+1/n) = f(x)[/tex](adsbygoogle = window.adsbygoogle || []).push({});

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# Interesting problem from my analysis class

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