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Interesting projectile problem

  1. Nov 3, 2005 #1
    Hello, I am practicing for the INternational Physics Olympiad qualifier and I was working on a practice test when I stumbles across what seemed like an easy problem. I thought It was super-intuitive, but I can't seem to verify a correct answer with the multiple choice selection. Here's the Problem:

    A ball ( or projectile, no matter) is thrown vertically with a velocity V. The ball reaches a maximum height h. In terms of h, at what height is the ball traveling at half of its initial velocity?

    Seemed easy at first, cause I knew and still know that it's a matter of plugging into the kinematics equations. the problem is that my logical setup isn't working out. I tried using the formula V^2=V0^2-2gh, but uh.... it's not workin out Can someone come to my rescue!?
     
  2. jcsd
  3. Nov 3, 2005 #2

    Doc Al

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    Staff: Mentor

    What's the problem? First figure out what h is in terms of V. Then try using that formula to find the new height.
     
  4. Nov 3, 2005 #3

    verty

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    Homework Helper

    The only hint I can give is to write formulas for h and h_2 and then get h_2 in terms of h.
     
  5. Nov 4, 2005 #4

    daniel_i_l

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    Gold Member

    In your equation V^2=V0^2-2gh the h that comes out is the hight when the ball gets to half oh the velocity (if V = 0.5 V0), with tht you can also find the total hight, the just divide the middle-speed hight with the final hight and find how they are related. For example if Hm = 3 and Hf = 4 then Hm/Hf = 3/4 so Hm = 3/4Hf
     
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