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matt grime

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what's wrong with that?

- Thread starter NewScientist
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- #26

matt grime

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what's wrong with that?

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- #28

HallsofIvy

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[tex]\Sigma log_{2^{2^n}} e[/tex]

That reduces to

[tex]\Sigma \frac{(-1)^n}{ln(2^{2^n}}= \Sigma \frac{(-1)^n}{2^n ln 2}= \frac{1}{ln 2}\Sigma \left(\frac{-1}{2}\right)^n[/tex]

which is, in fact, a simple geometric series.

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That's Beautiful.

HallsofIvy said:A couple of hours after my post (when I was not near a computer!) it suddenly dawned on me that NewScientist must have meant

[tex]\Sigma log_{2^{2^n}} e[/tex]

That reduces to

[tex]\Sigma \frac{(-1)^n}{ln 2^{2^n} }= \Sigma \frac{(-1)^n}{2^n ln 2}= \frac{1}{ln 2}\Sigma \left(-\frac{1}{2}\right) ^n[/tex]

which is, in fact, a simple geometric series.

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