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Interference in Thin Films (Need Urgent Help)

  1. Feb 2, 2006 #1
    A thin film of oil (n = 1.10) is located on a smooth, wet pavement. When viewed perpendicular to the pavement, the film appears to be predominantly red (640 nm) and has no component of wavelength 569 nm. How thick is the oil film?


    I have tried using 2nt=(m+1/2)wavelength but am having absolutely no luck in getting the right answer
     
  2. jcsd
  3. Feb 2, 2006 #2

    Meir Achuz

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    640 fits your formula.
    569 would fit the formula with the same m, but without the 1/2.
    Then solve for m and t.
     
  4. Feb 2, 2006 #3
    OK So:

    2.2t=(m+1/2)(640nm) and 2.2t=m(569 nm)

    How do I solve for m?
    I tried solving the second equation for t and then plugging it in to the first but still no luck.....
     
    Last edited: Feb 2, 2006
  5. Feb 3, 2006 #4

    Meir Achuz

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    The 569 formula could use m+1 instead of m, so that m will be positive.
    But then m should be an integer. I tried using m+N, but still can't get an integer for m. There must be a wrong number somewhere.
     
  6. Feb 3, 2006 #5

    jtbell

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    The oil film rests on water. That's where the "wet pavement" comes in. So the reflections from the front and back surfaces are both "external" reflections: at the top surface, the light goes from n=1 to n=1.1 (n increases, so it's external), and at the bottom surface, the light goes from n=1.1 to n=1.33 (again n increases so again it's external). Therefore there is no phase difference from the reflections. The phase difference comes completely from the path difference. You need to switch the two formulas around:

    [tex]2nt = m(640 nm)[/tex]

    [tex]2nt = (m+1/2)(569 nm)[/tex]

    This gives you pretty nearly an integer for m.
     
  7. Feb 3, 2006 #6

    nrqed

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    Just a general warning about this type of question: the two equations do not necessarily contain the same integer "m"!!! So the safe thing to do is to give them different names, m and m'.

    So there are really 3 unknowns (t, m and m'). Since you have only two equations, it might sound impossible to solve. But the fact that two of the unknowns are integers restrict the solutions and helps to solve the problem (although there are still an infinite number of solutions!!!)

    There are two possible approaches:

    a) In the first equation, plug in several values of m (0, 1, 2, etc) and calculate t. You get a list of possible t. Do the same thing with other equation (try several values of m' and calculate t). Looking at your two lists, you should quickly spot a value of t that appears in both. That`s your answer. (notice that if you kept going, you would find other matches but usually the prof wants the smallest value).

    b) Isolate t in one equation and plug in the other. Solve for the ratio m/m'. Usually it is an obvious rational number. For example you might get 1.33 in which case you know that m=4 and m'=3. (of course, it could also be 8 and 6 or 12 and 9, etc but again, one wants the smallest value, usually).


    Hope this helps .

    Pat
     
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