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Intergral problem! !

  1. Oct 26, 2009 #1
    Intergral problem! plz help!

    1. The problem statement, all variables and given/known data
    [tex]\oint[/tex](x: 0 to 1)[tex]\oint[/tex](y: [tex]\sqrt{}(1 - x^2)[/tex] to e[tex]\overline{}x[/tex]) xydydx

    The region bounded by y = e[tex]\overline{}x[/tex], y = [tex]\sqrt{}(1 - x^2)[/tex], and x =1
    3. The attempt at a solution
    i got stuck when i came to the part: 1/2 [tex]\oint[/tex](x: 0 to 1) (e^(2x) -1 + x^2)xdx
    i appreciate any help
     
  2. jcsd
  3. Oct 26, 2009 #2
    Re: Intergral problem! plz help!

    The symbol you are using is the symbol for a closed line integral. You should be using a normal integral sign: [tex]\int[/tex].
    Otherwise, since the integral is a linear operator, you have the following sum of integrals:
    [tex]\frac{1}{2}\left(\int xe^{2x} dx - \int x dx + \int x^3 dx\right)[/tex]
    Which one is giving you a problem?
     
  4. Oct 26, 2009 #3
    Re: Intergral problem! plz help!

    the first one xe^(2x) thing
    i guess it's intergral by part, but not sure
     
  5. Oct 26, 2009 #4
    Re: Intergral problem! plz help!

    I tried to do part and this is how i done (for the first intergral):
    u = x, du = dx, v = 1/2e^(2x), dv = e^(2x)dx
    uv - [tex]\int[/tex] vdu
    1/2xe^(2x) - [tex]\int[/tex] 1/2e^(2x)dx
    1/2xe^(2x) - 1/4(e^2 -1 )
    x runs from 0 to 1, but 1/2xe^(2x) is not in the intergral part, so how to eliminate x?
    very appriciate for more help!
     
  6. Oct 26, 2009 #5
    Re: Intergral problem! plz help!

    This entire expression is the indefinite integral; the entire expression must be evaluated at the endpoints of the integral if the integral is definite.
     
  7. Oct 26, 2009 #6
    Re: Intergral problem! plz help!

    got it! i didn't know that after spending 3 calculus classes, what a shame of me! thank you so much for your help and your time.
     
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