# Interior points

Hallo,

My teacher wrote that:

"The set has no interior points, and neither does its complement, R\Q" where R refers real

numbers and Q is the rationals numbers.

why can't i find an iterior point?

thanks,

Omri

Let q be an arbitrary rational number. Does there exist a neighborhood of q that is a subset of Q?

How about the fact that I can squeeze a real number between any two arbitrary points of Q?

HallsofIvy
Homework Helper
How about the fact that I can squeeze a real number between any two arbitrary points of Q?
Irrelevant. Do you mean an irrational number? Now that would be relevant.

HallsofIvy
Homework Helper
Hallo,

My teacher wrote that:

"The set has no interior points, and neither does its complement, R\Q" where R refers real

numbers and Q is the rationals numbers.

why can't i find an iterior point?

thanks,

Omri
So "the set" is Q. For p to be an interior point of Q, there must exist an interval around p, $$\displaystyle (p-\delta, p+\delta)[/quote] consisting entirely of rational numbers. For p to be an interior point of R\Q, the set of irrational numbers, there must exist an interval $(p- \delta, p+ \delta)$] consisting entirely of irrational numbers. There is NO interval of real numbers consisting entirely of rational number or entirely of irrational numbers.$$

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That was what I said anyway, but of course a real is not necessarily rational part got lost along the way... Sorry for that.

I'm sorry but the statement (as i guess you already assume) was:

"The set Q has no interior points, and neither does its complement, R\Q"

thanks

Omri

HallsofIvy