# Internal resistance problem

1. Sep 16, 2006

### FlipStyle1308

Here is the question I need to solve:

A battery has an emf E and an internal resistance r. When the battery is connected to a 25 ohm resistor, the current through the battery is 0.75 A. When the battery is connected to a 53 ohm resistor, the current is 0.45 A. Find the emf of battery and its internal resistance.

Okay, so I have a feeling I will be using the equation V = IR, but I don't knnow how to incorporate an internal resistance into the equation or approach. Can someone please help me outline the steps to solve this? Thanks!

2. Sep 16, 2006

### Gokul43201

Staff Emeritus
1. Treat the internal resistance as a resistor (r) in series with the battery (E).
2. Draw the circuit diagram for both cases.
3. Solve the two circuits - write down the two equations.
4. Solve for the 2 unknowns from the 2 equations.

Last edited: Sep 16, 2006
3. Sep 16, 2006

### FlipStyle1308

Would you be able to explain a bit more for step #1? How would my equation(s) be set up?

4. Sep 19, 2006

### Gokul43201

Staff Emeritus
You do not set up the equation until you have a circuit diagram. Once you draw the circuit as described in #1, you set up the equation using Kirchoff's voltage law (which is a fancy extension of Ohm's law): algebraic sum of all EMFs = algebraic sum of all voltage drops across resistors (these voltage drops calculated by Ohm's Law).

http://en.wikipedia.org/wiki/Kirchhoff's_circuit_laws