goWlfpack said:Homework Statement
A battery having an emf of 9.30 V delivers 103 mA when connected to a 60.0 ohms load. Determine the internal resistance of the battery.
Homework Equations
V = E - IR
The Attempt at a Solution
i plugged in 9.3 for V, .103 for I, and 60, for R... and i got 15.48. red x... any suggestions?
Internal resistance refers to the resistance within a battery's cells, which affects the flow of current and can cause a decrease in the battery's voltage. It is important to measure and understand internal resistance in batteries because it can impact the battery's performance and overall lifespan.
Internal resistance can be calculated by using Ohm's Law, which states that resistance (R) is equal to voltage (V) divided by current (I). Therefore, internal resistance (r) can be calculated by dividing the change in voltage (ΔV) by the change in current (ΔI). This can be represented as r = ΔV/ΔI.
The formula for solving for battery emf (electromotive force) is E = V + Ir, where E is the emf, V is the voltage across the battery terminals, I is the current flowing through the battery, and r is the internal resistance.
The load resistance in a circuit can be found by using Ohm's Law, which states that resistance (R) is equal to voltage (V) divided by current (I). Therefore, the load resistance (R) can be calculated by dividing the voltage across the load (V) by the current flowing through the load (I). This can be represented as R = V/I.
Several factors can affect the internal resistance in batteries, including the type and age of the battery, the temperature, and the chemical composition of the battery's cells. Additionally, high or low levels of charge can also impact the internal resistance of a battery.