- #1
whitehorsey
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1.
3. I solved for t distribution = (.03 - 0)/(.1/√25) = .15
P - Value = 2P(T ≥ .15) = 2(.441) = .882. So I got No but instead we fail to reject H0 because 0.882 > .05 (.005 is the typical significance level). Is this correct and would it be a correct interpretation?
3. I solved for t distribution = (.03 - 0)/(.1/√25) = .15
P - Value = 2P(T ≥ .15) = 2(.441) = .882. So I got No but instead we fail to reject H0 because 0.882 > .05 (.005 is the typical significance level). Is this correct and would it be a correct interpretation?