To find the intersection of two lines in R3, you set the lines equal, right?(adsbygoogle = window.adsbygoogle || []).push({});

[a,b,c] + d[e,f,g] = [h,i,j] + k[l,m,n]

Then split these into three equations,

1. a + d(e) = h + k(l)

2. b + d(f) = i + k(m)

3. c + d(g) = j + k(n)

And solve for k and d, correct?

If k and d are consistent, then these values are used to find the point of intersection.

My question is: Is this same method used in R4, with two lines of 4 dimensions?

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# Intersection of Lines in R4

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