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Homework Help: Intersection of surfaces/tangent vector

  1. Oct 13, 2004 #1
    Hi, how do I find a tangent vector to the curve intersection of the surfaces [itex]2x^2+2y^2-z^2=25[/itex] and [itex]x^2+y^2=z^2[/itex] which has positive x-direction?

    Thanks in advance.
     
  2. jcsd
  3. Oct 14, 2004 #2

    arildno

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    Note that your last equation implies that we may write:
    [tex]x=z\cos\theta,y=z\sin\theta,0\leq\theta\leq2\pi[/tex]
    Inserting these relations into your first equation, yields:
    [tex]z^{2}=\frac{25}{3}[/tex]
    Can you take it from here?
     
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