1. The problem statement, all variables and given/known data A 15,000 kg loader traveling east at 20 km/h turns south and travels at 25 km/h. Calculate the change in the loader’s a. kinetic energy. b. linear momentum. 2. Relevant equations KE=(1/2)mv^2 p=mv p(i)=p(f) : I am assuming I can ignore gravity 3. The attempt at a solution I know there is already a thread for this problem but I am having trouble understanding how to describe the change in linear momentum, I feel okay with part a: a) 20km/hr = 5.56m/s 25km/hr=6.94 m/s KE2-KE1 1/2mv2^2 - 1/2mv1^2 1/2 (15000)(6.94)^2 - 1/2(15000)(5.56)^2 361227-231852 129375J But for part b I am confused as to what to quantify as the change in linear momentum. So far I have: b) p(east) = mva (15000kg)(5.56m/s) 83400 kg*m/s p(south) = mvb (15000kg)(6.94m/s) 104100 kg*m/s And then I used pythagorean and inverse tan to find a resultant momentum of 1.3 * 10^5 with an angle of 51 degrees south of east. Is this my final answer? Do I need to subtract this from the initial momentum in the easterly direction? Why or why not? Any help is appreciated, thanks!!!