- #1

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I'm not quite sure where to start with this.

Thank you in advance

- Thread starter lab-rat
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- #1

- 44

- 0

I'm not quite sure where to start with this.

Thank you in advance

- #2

Hootenanny

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You must have some idea as to where to start. We can't help you unless you at least

I'm not quite sure where to start with this.

Thank you in advance

- #3

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- #4

lewando

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You can start by looking on the interweb for things like "measuring the diameter of a molecule".

- #5

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Here's my attempt:

(a) Area of slick = [itex]\pi[/itex]r

diameter of slick = 2x10

volume of slick= area x thickness

volume of oil=volume of slick= 1L = 0.001m

0.001m

r=1261.57m

d=2523m

(b) [itex]\rho[/itex]=M/V

V=[itex]\pi[/itex]r

=[itex]\pi[/itex](1x10

V=3.14x10

M=850kg/m

M=2.67x10

does that make sense?

- #6

lewando

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Looks okay, too many significant digits though.(a) Area of slick = [itex]\pi[/itex]r^{2}

diameter of slick[you mean thickness of slick]= 2x10^{10}

volume of slick= area x thickness

volume of oil=volume of slick= 1L = 0.001m^{3}

0.001m^{3}=([itex]\pi[/itex]r^{2}

r=1261.57m

d=2523m

V=[itex](4/3)\pi[/itex]r(b) [itex]\rho[/itex]=M/V

V=[itex]\pi[/itex]r^{3}

=[itex]\pi[/itex](1x10^{-10})^{3}

V=3.14x10^{-30}m^{3}

M=850kg/m^{3}x 3.14x10^{-30}m^{3}

M=2.67x10^{-27}kg

does that make sense?

- #7

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The diamete/thickness was a typo, I wrote it properly on my sheet :)

As for the significant digits, does 2.5x10

- #8

lewando

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If you are using a number like 2x10^{-10}, I think one SD would suffice.

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