Having some trouble with the last part of this question: A ball is projected horizontally from the edge of a table that is 1.11 m high, and it strikes the floor at a point 1.36 m from the base of the table. What is the initial speed of the ball? How high is the ball above the floor when its velocity vector makes a 46.4o angle with the horizontal? So I've got the answer to the first part (yea me) by doing this: First I solved for time, and got an answer of 0.476 seconds (I know I'm cheating by not typing the wquation out but I'm not sure how to type out square roots and intiial velocities and all those lovely little signs) Then I went: Delta x = v(intitial)(cos theda int)t v=1.36 m / 0.476 s v = 2.86 m/s So I've got my initial velocity of 2.86 m/s. So my problem comes with this second part of the questionow high is the ball above the floor when its velocity vector makes a 46.4o angle with the horizontal? So I think I would be looking for Vy at 46.4 degrees, but I'm not sure how to find that, because all of the equations I know only contain initial theda, not some random theda along the way. Is this solved witha projectile motion equation, is it a purely vector related question, or a combination of both? Should I be using other information in the question? Any guidance is greatly appreciated! Thanks!