- #1
AJME
- 3
- 0
Hi Guys,
I am new to Electrical Engineering and am trying to figure out the voltages for (1) (2) (3) in the link below, assuming that a 5V dc power supply is connected to the terminals on the left. I am new to Elec Engineering and am struggling a bit. I thought to try Node Voltage analysis to get the answers. Obviously (1) =5V
However for (2), I am not sure how to figure out the equations.
Link is
http://photobucket.com/albums/a339/Eliatamby/?action=view¤t=SV400003.jpg
I was thinking the KCL equation at node (2) would be:
(v1-v2)/100 = v2/3900 + (v2-v3)/220
Also, I have a general question. For the current entering node (2) can't I get uses Ohm's Law at the 100Ohm resistor? E.g. 5/100 so the current entering v2 would be 0.05 A. Then I could sub this into the (v1-v2)/100 equation to find out the value of v2? Would that work?
Thanks for your help, please let me know if this is not clear
I am new to Electrical Engineering and am trying to figure out the voltages for (1) (2) (3) in the link below, assuming that a 5V dc power supply is connected to the terminals on the left. I am new to Elec Engineering and am struggling a bit. I thought to try Node Voltage analysis to get the answers. Obviously (1) =5V
However for (2), I am not sure how to figure out the equations.
Link is
http://photobucket.com/albums/a339/Eliatamby/?action=view¤t=SV400003.jpg
I was thinking the KCL equation at node (2) would be:
(v1-v2)/100 = v2/3900 + (v2-v3)/220
Also, I have a general question. For the current entering node (2) can't I get uses Ohm's Law at the 100Ohm resistor? E.g. 5/100 so the current entering v2 would be 0.05 A. Then I could sub this into the (v1-v2)/100 equation to find out the value of v2? Would that work?
Thanks for your help, please let me know if this is not clear