1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Intro to Physics: Fluids

  1. Nov 19, 2007 #1
    I have solved this problem but am not sure where I'm going wrong here...


    Suppose you pour water into a container until it reaches a depth of 20cm . Next, you carefully pour in a 9.7cm thickness of olive oil so that it floats on top of the water.

    What's the pressure at the bottom of the container? Express anser using two significant figures.

    P-P_atm= ? Pa

    P_1= P_atm + (rho)(g)(h)
    = 1.013 x 10^5 Pa + (920kg/m^3)(9.81m/s^2)(0.097m)
    = 102175.44 Pa

    P=P_1 + (P_water)(g)(h)
    = 1.013 x 10^5 Pa + (1000kg/m^3)(9.81m/s^2)(0.20cm)
    = 104137 Pa

    I keep getting this answer wrong.. I do not know what I am doing wrong. Please help!
    I've tried already 1.04x10^5
    1.0x10^5
    and the above exact number.
     
  2. jcsd
  3. Nov 19, 2007 #2

    Doc Al

    User Avatar

    Staff: Mentor

    The pressure at the bottom is the sum of:
    - atomospheric pressure
    - pressure due to .097 m of olive oil
    - pressure due to .20 m of water
     
  4. Nov 20, 2007 #3
    Thanks! I have discovered what I did wrong...I was not supposed to include atmospheric pressure in the first place. Thank you, Doc Al.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Intro to Physics: Fluids
  1. Intro physics question (Replies: 2)

  2. Intro Physics question (Replies: 7)

  3. Intro uni physics (Replies: 3)

Loading...