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Introduction to Oscillations

  1. Nov 29, 2006 #1
    1. The problem statement, all variables and given/known data

    Now assume that the x coordinate of point R is 0.12m and the t coordinate of point K is 0.0050 s.

    What is the period T ?

    2. Relevant equations

    T = 1/f where f is the frequency and T is the period.

    3. The attempt at a solution

    From the graph, there are 2 periods in oscillation. So I guess that the period would be 2T and since it starts at R = .12m and reaches point K in .0050 s . So the velocity is .12m/.0050 s = 24m/s

    Not sure if this is correct but, T = 2T = .12m/.005s = T = 12 s

    Attached Files:

  2. jcsd
  3. Nov 29, 2006 #2


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    Staff: Mentor

    No. The horizontal distance from 0 to K is a quarter of the period of that sinusoidal waveform. Since you are given the time difference from 0 to K, and that is a quarter of the period, what is the total period?
  4. Nov 29, 2006 #3
    Thank for the help

    From what you have said, I can calculate the total period to be (.005)4 = .02s
  5. Nov 29, 2006 #4


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    Staff: Mentor

    Good. Quiz Question -- what is special about that period?
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