Question: A 25 mL sample of H2C204 solution required 19.62 mL of 0.341 M NaOH for neutralization. Calculate the molarity of the acid? The reaction was : H2C204 + 2NaOH ---------------------> Na2C2O4 + 2H2O Attempt: [Which line has the mistake in it and what is it?] converted 25mL to L converted 19.62 to L multiplied 0.01962 by 0.341 m/L of NaOH and multiplying all of that by 1 mol of H2C204 / for every 2 moles of NaOH multplied all of that by .025 L to get 0.00323 moles of the H2C204 , they said they wanted the molarity so molarity is moles/liter of solution, you get .00323/0.025L = .129 Molarity of H2C204 THE ANSWER CAME OUT WRONG??????? WHAT the heck??!?!? Why??? Which line has the mistake in it and what is it? The answer is supposed to be 0.134 right?