Problem: Reactor operating at 2300 MW with specific power of 24.42 MW/MT, was shutdown on 1 January 2009. The reactor was fueled with 93.3 MT of uranium with initial enrichment of 3.8% U-235. At shutdown, core burnup 23.3 GW-day/MT. Question: 1.What was inventory of Cs-137 when the reactor was shutdown? 2.How much Cs-137 will be left on 4 March 2009? Actions: Honestly, i have hard time understanding what is going here. 1.I thought that this is how many moles of the fission product Cs-137 does this reactor produce per day? 2.How much left is N(t)=N0*(0.5)t/t0.5? I need to plug in t here 4 March 2009 - 1 January 2009. Right? Steps: 1. 1 mole fissioned =223 MWD 2300/223= 10.31 moles of fissioned per day 6.19 atoms of Cs-137 per 100 fissions. 10.31*0.00619=.6384304 moles of Cs-137 produced per day. A=λN=(ln2)(.60222*1024)*(1/(365*24*3600*30.07)) Am i on the right track? Thanks in advance.