Suppose that an X ray has initial energy Eγ=100keV, and the incident (relativistic) electron has energy Ee=100GeV. Compute the final energy of the photon E'γ assuming the final direction of the photon makes an angle θ=Π with the initial direction.
For solving this problem, use the conservation of energy and each component of the momentum.
None yet - still setting up problem.
The Attempt at a Solution
I am familiar with normal Compton scattering where a photon interacts with a rest electron, but not the inverse.
Maybe this works a certain way, but here is how I see it and what I want to verify.
I picture relativistic electron moving along the x-axis and getting rear ended by the x ray. The resulting gamma ray goes the other direction, still along x, and the electron continues moving along the x-axis with much less energy and momentum. At least that's what I hope because it makes the problem easier - although I am pretty sure that is wrong.
So a more realistic view is the electron is coming in at an angle and leave at an angle with the resulting photon going the opposite direction but still along the x-axis.
Is there a relationship between the initial angle and the resulting angle of the electron? I have it half setup but end up with way too many unknowns.