Inverse cosine function.

  • Thread starter Mynona
  • Start date
  • #1
3
0

Main Question or Discussion Point

I have a cosine function, namely the function for oscillation x=A cos(wt).

I want to separate the t out here, so I can solve for it. My teacher gave the the answer to be t= (arccos (x/a)/2pi)*T, but I can't quite see where he came up with that. Would anyone be as kind as to give me a more elaborate explanation of how this transition was made.


(2pi and T comes from w=2pi/T).

Sorry for bad English, not a native English speaker obviously :)
 

Answers and Replies

  • #2
Cyosis
Homework Helper
1,495
0
The inverse function of the cosine is the arc cosine. If a function [itex]f(x)[/itex] has an inverse [itex]f^{-1}(x)[/itex] then [itex]f^{-1}(f(x))=f(f^{-1}(x))=x[/itex].

Divide the equation on both sides by A then take the arccos on both sides. Can you calculate [itex]\arccos(\cos(\omega t)) [/itex]now?
 

Related Threads for: Inverse cosine function.

  • Last Post
Replies
2
Views
2K
Replies
2
Views
1K
Replies
2
Views
815
  • Last Post
Replies
3
Views
817
Replies
1
Views
3K
  • Last Post
Replies
5
Views
2K
  • Last Post
Replies
1
Views
589
Top