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Inverse Fourier Transform

  1. Aug 2, 2007 #1
    Can someone help me and tell me the steps to solve the inverse Fourier transform of the following function

    (10*sin(3*omega)) / (omega+Pi)

  2. jcsd
  3. Aug 2, 2007 #2
    You will need to integrate "this function times exp(i*omega*t)" over omega from -inf to +inf. The resulting thing is a function of t, which is in the time domain, as usually called.
  4. Aug 2, 2007 #3
    How would I work this out by hand? I know you probably need to use trig identities in order to simplify the problem. Do you have any suggestions.
  5. Aug 2, 2007 #4
    you know exp(iwt)=cos(wt)+i*sin(wt); then you're right, triangle idents are needed. Just treat i as a constant, and it won't hurt other calculation.
  6. Aug 2, 2007 #5
    I'm still just confused of how to get a simplified answer. Do you have time to work the problem out and let me know what sort of answer you get?

    Thanks for all your help.
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