- #1

cathode-ray

- 50

- 0

## Homework Statement

Hi!

I tried to get the inverse fourier transform of the function:

[itex]X(j\omega)=1/(jw+a)[/itex]

for a>0, using the integral:

[itex]x(t)=(1/2\pi)\int_{-\infty}^{+\infty} X(j\omega)e^{j\omega t}d\omega[/itex]

I know that the inverse Fourier transform of [itex]X(j\omega)[/itex] is:

[itex]x(t)=e^{-at}u(t), a>0[/itex]

but when i tried to calculate the integral i got:

[itex]x(t)=(1/2\pi)\int_{-\infty}^{+\infty} e^{j\omega t}/(jw+a)[/itex]

,and i wasnt able to get that integral using any of the techniques i know. What am i doing wrong or isnt possible to get the inverse Fourier transform of that function this way?