1. The problem statement, all variables and given/known data Let f(x) = 1−3x−2x^2 , x ∈ [−2, −1]. Use the Horizontal Line Test to show that f is 1–1 (on its given domain), and find the range R of f. Then find an expression for the inverse function f −1 : R → [−2, −1]. 3. The attempt at a solution I have already done the horizontal line test but I am unsure about my working out for the other parts below would the range just be: f(-2)=-1 f(-1)=2 y ∈ [−1, 2] finding expression for inverse function 1−3x−2x^2=y -2x^2-3x-y+1=0 using quadratic formula x=(3-sqrt(-8y+17)/4 as (3+sqrt(-8y+17)/4 lies outside the range Is this correct?