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I can only find two answers for this equation, whereas the books says it should be four. Can someone enlighten me? Showing the procedure would help:P
(degrees)
sec(2x+180) = 2 0<x<360
(degrees)
sec(2x+180) = 2 0<x<360
Galileo said:First write it as cos(2x+180)=1/2.
Then get rid of the 180 (the 180 causes a shift in the graph of cos(2x)).
That's what I meant by 'getting rid of the 180'.OlderDan said:You could change the cosine to -cos(2x) = 1/2
An inverse function is a function that "undoes" the action of another function. In other words, given a function f(x), the inverse function would return the value of x that was originally input into f(x). In mathematical notation, the inverse function is denoted as f^-1(x).
To solve inverse functions, you can use the following steps:
1. Rewrite the equation in the form of f(x) = y.
2. Switch the x and y variables.
3. Solve for y.
4. Replace y with f^-1(x) to get the final inverse function.
The inverse of the secant function is the cosine function, cos(x). This means that if you input a value into the cosine function, the output will be the angle whose secant is equal to that value.
To solve for x in this equation, we can follow these steps: Yes, there can be multiple solutions for an inverse function. In this case, since the given range is 0
1. Subtract 180 from both sides to get sec(2x) = -178.
2. Take the inverse secant of both sides to get 2x = sec^-1(-178).
3. Divide both sides by 2 to get x = 0.5 * sec^-1(-178).
4. Use a calculator to find the inverse secant of -178, which is approximately -1.577 radians or -90.4 degrees.
5. Since the given range is 05. Is there more than one solution for this inverse function?
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