- #1

- 25

- 0

I have this problem:

find the inverse laplace transfor for

Y1(s) = exp(-s)/s^2

Y2(s) = {1/[4*(s+1)]}*exp(-2*s)

my solution is:

using the 2nd shifting theroem

y1(t) = (t-1) H(t-1)

y2(t) = (1/4)*exp(2-t)*H(t-2)

Is my solution correct?

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- Thread starter Neoon
- Start date

- #1

- 25

- 0

I have this problem:

find the inverse laplace transfor for

Y1(s) = exp(-s)/s^2

Y2(s) = {1/[4*(s+1)]}*exp(-2*s)

my solution is:

using the 2nd shifting theroem

y1(t) = (t-1) H(t-1)

y2(t) = (1/4)*exp(2-t)*H(t-2)

Is my solution correct?

- #2

- 25

- 0

I want to clarify that H(t-1) and H(t-2) is the Hiviside function.

- #3

- 809

- 0

I want to clarify that H(t-1) and H(t-2) is the Hiviside function.

What is the laplace transform of?

y1(t) = (t-1) H(t-1)

y2(t) = (1/4)*exp(2-t)*H(t-2)

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