1. PF Contest - Win "Conquering the Physics GRE" book! Click Here to Enter
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Inverse laplace transform

  1. Feb 5, 2010 #1
    ok im given the problem ((s/s^2+4)+s+5))/(s^2+6s+18) I use the expand function of my ti-89 and get
    ((163/70)*s)/((s+3)^2+9) + ((398/85))/((s+3)^2+9) + ((7/170)*s)/(s^2+4) + (6/85)/(s^2+4)
    1st term--------------------2nd term-----------------3rd term-------------4th term

    ok my issue is with the second term when i do the translation i get -2741/1190 I then want it to be 3 because of k so i get a coefficient of (2741/3570) but my calculator says it should be

    All the other terms are correct just this coefficient on second term

    Any help?
  2. jcsd
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted