# Inverse laplace transform

1. Jun 6, 2012

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2. Jun 6, 2012

### algebrat

those denominators are equal, trust me. Are you experiecned with completing the square; it's a good method to have down for calculus. Here's how I would have gone about it.

$x^2-2x+5=x^2-2x+1+4=(x-1)^2+4$

Right? Because to copmplete the square you take half of -2 and square it, which is 1.