- #1

- 42

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U(s,t)=U(s,0)*exp[s^2*t]

Transformation from U(s,t) to u(x,t).

I don't know if this inverse transformation exit or not.

Thank you very much.

- Thread starter germana2006
- Start date

- #1

- 42

- 0

U(s,t)=U(s,0)*exp[s^2*t]

Transformation from U(s,t) to u(x,t).

I don't know if this inverse transformation exit or not.

Thank you very much.

- #2

- 12,997

- 550

How does U(s,0) look like as a function ?

Daniel.

Daniel.

- #3

- 42

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U(s,0) come from the boundary conditions, u(x,t=0)=u(x)=deltadirac(x)

- #4

- 6

- 0

You can fix U(s,0), but the e hat a singularity in infinity.

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