Inverse of a function

  • #1

danago

Gold Member
1,123
4
Hi. The question wants me to find the inverse of [tex]
y = \frac{{x - 1}}{{x - 2}}
[/tex]

Heres my working for it:
[tex]
\begin{array}{l}
x = \frac{{y - 1}}{{y - 2}} \\
xy - 2x = y - 1 \\
xy - y = 2x - 1 \\
(x - 1)y = 2x - 1 \\
y = \frac{{2x - 1}}{{x - 1}} \\
\end{array}
[/tex]

The answer says something different though.

If anybody could please tell me where I am going wrong, or perhaps if the answer book is wrong, id greatly appreciate it.

Thanks,
Dan.
 
  • #2
Ahh nevermind sorry.

My stupid mistake. The answer said [tex]
y = \frac{{1 - 2x}}{{1 - x}}
[/tex] which i just realized is exactly the same thing.

Thanks anyway :)
 

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