1. The problem statement, all variables and given/known data Given f(x) = x2+3x+2, what is f-1(f(x))? 2. Relevant equations 3. The attempt at a solution Algebraically, getting f-1(x) is as follows: y=x2+3x+2 x=y2+3x+2 y=+/-√(x+0.25)-1.5 f-1(x)=+/-√(x+0.25)-1.5 f-1(f(x))=+/-√(x2+3x+2+0.25)-1.5 f-1(f(x))=+/-√(x+1.5)2-1.5 f-1(f(x))=x or -x-3 I thought f-1(f(x)) was always x. What's wrong with -x-3?