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Inverse of Airy?

  1. Apr 7, 2009 #1
    Quick question. I'm not even sure if what I've done so far is right, but if it is, then I have
    [tex]"Ai" ((s^{2/3} d)/z_0 )= "Ai" ( -s^{2/3} ) e^{-1}[/tex]
    and I want to find out what d is. Is there a simple way to disentagle this? d is greater than z_0, and s is positive, so this gives me a positive argument on the left, and negative on the right if that helps. I don't expect an answer back in time as this is due in not very long, but it's one of the few things that I've really been stumped on, and hoping someone can get back to me in time. Cheers. :)
     
  2. jcsd
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