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Inverse Operator

  1. May 25, 2007 #1


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    Don't know if i'm wrong or this makes sense but if:

    [tex] \frac{1}{D}f= \int dx f(x) [/tex]

    Where D is the derivative operator and the integral is indefinite, my question is if as a generalization of this then:

    [tex] \frac{1}{D_{x}+D_{y}}f= \iint dxdy f(x,y) [/tex]

    (Double indefinite integral over x and y) and so on ....
  2. jcsd
  3. May 25, 2007 #2

    matt grime

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    Did you even try it on a few examples?
    Last edited by a moderator: May 25, 2007
  4. May 26, 2007 #3


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    I have tried this:

    [tex] \frac{1}{D_{x}+D_{y})f=g [/tex]

    then we can put it in the form:

    [tex] \frac{\partial g}{\partial x}+\frac{\partial g}{\partial y}=f [/tex]

    HOwever i don't know how to solve this PDE to get 'f'
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