# Inverse Operator

1. May 25, 2007

### tpm

Don't know if i'm wrong or this makes sense but if:

$$\frac{1}{D}f= \int dx f(x)$$

Where D is the derivative operator and the integral is indefinite, my question is if as a generalization of this then:

$$\frac{1}{D_{x}+D_{y}}f= \iint dxdy f(x,y)$$

(Double indefinite integral over x and y) and so on ....

2. May 25, 2007

### matt grime

Did you even try it on a few examples?

Last edited by a moderator: May 25, 2007
3. May 26, 2007

### tpm

I have tried this:

$$\frac{1}{D_{x}+D_{y})f=g$$

then we can put it in the form:

$$\frac{\partial g}{\partial x}+\frac{\partial g}{\partial y}=f$$

HOwever i don't know how to solve this PDE to get 'f'