# Inverse Operator

Don't know if i'm wrong or this makes sense but if:

$$\frac{1}{D}f= \int dx f(x)$$

Where D is the derivative operator and the integral is indefinite, my question is if as a generalization of this then:

$$\frac{1}{D_{x}+D_{y}}f= \iint dxdy f(x,y)$$

(Double indefinite integral over x and y) and so on ....

matt grime
$$\frac{1}{D_{x}+D_{y})f=g$$
$$\frac{\partial g}{\partial x}+\frac{\partial g}{\partial y}=f$$