The intensity (I) of sunlight (the received power per unit area) drops with distance (d) from the sun according to the inverse square law - i.e I2/I1 is proportional to (d1/d2)^2
What is the total power received at Earth (above the atmosphere) per unit of surface area?
P.S. The wavelength of peak emission from the surface = 4.99655x10^-7 m
AND the total radiated power per unit of surface area of the sun = 3.901x10^26
Inverse square law
The Attempt at a Solution
Work out distance from earth to sun and square it? Im really not sure how this formula works, I havent used it before.