# Inverse square potential

Do exist examples of attraction forces with such a type potential
##V(\boldsymbol r)\sim-\frac{1}{|\boldsymbol r|^2}, \quad |\boldsymbol r|\to 0##
in physics ?

Homework Helper
Do exist examples of attraction forces with such a type potential
##V(\boldsymbol r)\sim-\frac{1}{|\boldsymbol r|^2}, \quad |\boldsymbol r|\to 0##
in physics ?
Just spit-balling here... An inverse square potential would imply an inverse cube force law. What do we have for inverse cube forces?

How about the electrostatic force on (or from) a dipole. That should scale as the differential of an inverse square, i.e. as an inverse cube.

jim mcnamara and Dale
Thanks. Actually I need physics examples at least such that

Mentor
How about the electrostatic force on (or from) a dipole. That should scale as the differential of an inverse square, i.e. as an inverse cube.
Excellent response. You could do arbitrary order multipoles to get any n>0 desired

Homework Helper
Thanks. Actually I need physics examples at least such that
I am not sure how the suggestion of a dipole fails to satisfy that requirement.

It is a net attractive force and consequently has a negative potential everywhere referenced to zero at infinity. So the sign is right. It approximates an inverse square potential. So the approximation is right (when r >> size of dipole). And n=2 which satisfies n>=2.

Mentor
Look up the "multipole expansion" used in molecular physics (for example, in the textbooks by Demtröder).

You get a ##-1/R^2## potential for ion-dipole interaction, ##-1/R^3## for dipole-dipole, ##-1/R^4## for ion-induced dipole, and so on.

Thank you everybody so much!

It seems I still have some stupid questions. I have been thinking that dipole is the potential of the type ##V=\frac{\cos\varphi}{r^2}## (in polar coordinates) but this potential changes sign.
Could you please be more detailed?

Homework Helper
It seems I still have some stupid questions. I have been thinking that dipole is the potential of the type ##V=\frac{\cos\varphi}{r^2}## (in polar coordinates) but this potential changes sign.
Could you please be more detailed?
In simple terms, a "dipole" would be a pair of equal and opposite charges with some fixed separation. For example, a positive charge and an equal negative charge on opposite ends of an insulating stick.

The net charge of this dipole is zero. And we can consider its location to be the midpoint between the two charges.

Now add a fixed positive point charge at the origin of your coordinate system and have this dipole floating in space somewhere. One could use a negative point charge instead. It changes nothing. What is the force of the point charge on the dipole?

Well, the dipole is going to rotate under the influence of the field so that the negative end faces the central charge and the positive end faces away. That means that your ##cos\varphi## term goes away.

Edit: Apologies for the length and the simple mindedness of the response. I was talking my way through it until I finally got to the point of understanding how you'd arrived at your formulation.

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