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Inverse trig derivative

  • Thread starter mmh37
  • Start date
  • #1
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DOES ANYONE SEE WHY MY LATEX FORMULAE ARE NOT BEING GENERATED?

I was wondering how one can differentiate the following:

[tex] arctan (x/y) [/tex]

wrt y

is it just inner times outer derivative, i.e.

[tex] (-x) /((1 + x^2/y^2)*y^2) [/tex]

in the definitions I found they just gave examples like

[tex] tan^(-1) y [/tex]

thanks very much
 
Last edited:

Answers and Replies

  • #2
TD
Homework Helper
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mmh37 said:
DOES ANYONE SEE WHY MY LATEX FORMULAE ARE NOT BEING GENERATED?
LaTeX is currently down but I was able to follow your problem through the code.

If x and y are independant variables then you differentiate wrt to y, just by using the chain rule.
Your answer is correct and can be simplified to -x/(x²+y²).
 

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