- #1

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h(t)=sin(arccos t)

I just don't know where to start. I'm thinking chain rule. The solution shows

sqrt(1-t^2) as the next step. I am not following how they did that.

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- Thread starter NIZBIT
- Start date

- #1

- 69

- 0

h(t)=sin(arccos t)

I just don't know where to start. I'm thinking chain rule. The solution shows

sqrt(1-t^2) as the next step. I am not following how they did that.

- #2

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- #3

TD

Homework Helper

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Or: remember that cos²a+sin²a = 1.

- #4

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- #5

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- #6

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- #7

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So I should solve for sin using that identity. Then sub for t and get sqrt(1-t^2)?

- #8

HallsofIvy

Science Advisor

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