- #1
Struggling
- 52
- 0
hi,
my problem is i have equations like determine the derivative of:
a. arcsin 1/x
b. arcsin x^(1/2)
c. arcsin x^(-1/2)
etc etc.
and i have the formulas for the trigs such as:
d/dx arcsinf(x) = 1/(1-f(x)^2)^1/2 x f'(x) and i have the arcos and asrctan one.
but when i put f(x) into the equations eg:
arcsin^(1/2):
1/ (1-x^1/2)^1/2 x 1/2x^-1/2
i can never get the answer i know I am multiplying wrong and possibly using the powers wrong because and example the teacher used was:
y = arctan 3/x^2 find y'
f(x) = 3x^-2
f'(x) = -6x^-3
y'= 1/1+(3x^-2)^2 x (-6x^-3)
therefore: y' = -6x/ x^4 + 9
how did he get the final answer from y'= 1/1+(3x^-2)^2 x (-6x^-3)? I am totaly confused I've been trying to work it out for days any help would be appreciated thanks
my problem is i have equations like determine the derivative of:
a. arcsin 1/x
b. arcsin x^(1/2)
c. arcsin x^(-1/2)
etc etc.
and i have the formulas for the trigs such as:
d/dx arcsinf(x) = 1/(1-f(x)^2)^1/2 x f'(x) and i have the arcos and asrctan one.
but when i put f(x) into the equations eg:
arcsin^(1/2):
1/ (1-x^1/2)^1/2 x 1/2x^-1/2
i can never get the answer i know I am multiplying wrong and possibly using the powers wrong because and example the teacher used was:
y = arctan 3/x^2 find y'
f(x) = 3x^-2
f'(x) = -6x^-3
y'= 1/1+(3x^-2)^2 x (-6x^-3)
therefore: y' = -6x/ x^4 + 9
how did he get the final answer from y'= 1/1+(3x^-2)^2 x (-6x^-3)? I am totaly confused I've been trying to work it out for days any help would be appreciated thanks