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Inverse trig equation

  1. Dec 14, 2009 #1
    1. The problem statement, all variables and given/known data

    I have knocked a problem down to:

    [tex]-arcsec \frac{3x}{4}[/tex]

    but my textbook gives the answer as:

    [tex]arctan \frac{4}{\sqrt{9x^2 - 16}}[/tex]

    Are these somehow equivalent?


    2. Relevant equations

    3. The attempt at a solution
  2. jcsd
  3. Dec 14, 2009 #2


    Staff: Mentor

    I don't think so. However, I get arccsc (3x/4) being equal to arctan(4/sqrt(9x^2 - 16))
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