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Homework Help: Inverse trig

  1. Sep 27, 2009 #1

    implict dif

    can somone please verify
  2. jcsd
  3. Sep 27, 2009 #2


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    You're differentiating sin^-1y with respect to x, so you use the chain rule and first differentiate with respect to y, then derive y with respect to x, then multiply the two derivatives together. That would give you 1/sqrt(1-y^2) * dy/dx, not 1/sqrt(1-x^2) *dy/dx
  4. Sep 28, 2009 #3
    ah yes that was a typeo on my part my solution is

    my book is showing

    which divides (1-y^2)^(1/2)-e^x into x not just x/(1-y^2)^(1/2) i dont believe these solutions are equal
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