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1. [tex]\int \frac{dx}{\sqrt{1 - x^2}} = sin^-1 x + C[/tex]

So the derivative of [tex]sin^-1x[/tex] is [tex]\frac{dx}{\sqrt{1 - x^2}}[/tex]?

The -1 are exponents. It isn't working.

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# Inverse Trigonometric Formulas

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