- #1
- 162
- 0
Let A and B be n × n matrices.
a. Show that if A is invertible and AB = 0, then
B = 0.
If A is invertible, it can be reduced to the I matrix.
Thus IB=0 (this is the part where I'm hesitant, can I say that IB=0?)
Thus B=0 since I≠0
a. Show that if A is invertible and AB = 0, then
B = 0.
If A is invertible, it can be reduced to the I matrix.
Thus IB=0 (this is the part where I'm hesitant, can I say that IB=0?)
Thus B=0 since I≠0