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Inverting Op Amp Circuit

  • Thread starter AdkinsJr
  • Start date
1. The problem statement, all variables and given/known data

Write output voltage in terms of input voltages for the circuit drawn.

I drew the circuit and then feed back loop.


circuit-9_4 (1).png

2. Relevant equations

Ohms Law V=IR
Basic Properties of Op Amps (ideal), voltages are assumed equal at both inputs...

3. The attempt at a solution

The difficulty is that there should be two currents that need defining, but I'm not sure how to eliminate both of them. I wrote two equations for the current through the feedback loop and then equated to write Vout in temrs of the resistances and Va.

[tex]I_a = \frac{V_{out}-V_a}{R_2} [/tex]
[tex]I_a = \frac{V_a-V_{out}}{R_1}[/tex]
[tex]V_{out}=\frac{V_a-V_{in}}{R_1}R_2 +V_a[/tex]

I can't figure out how to write Va in terms of Vin and the resistances at this point. The only other relationships between Va and other quantities come from the fact that [tex]V_b=I_bR_3[/tex] which means that [tex]V_a=I_bR_3[/tex] also, but I still need to get rid of the current Ib now, so that doesn't help much. I can't figure out what I'm missing. Any help would be great.
 
There's a mistake in the feed back loop in my drawing, the ground at the end of R2 should not be there, that should be Vout.
 

gneill

Mentor
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You've listed one useful property for the op-amp in a negative feedback situation. What other property might be useful?
 

LvW

758
193
Have a look on the second equation. Obviously, it is wrong (Vout mixed-up with Vin).
More than that, you can forget the influence of R3 (because an ideal amplifier with infinite input resistance is assumed). Hence, you can set Va=Vb=0.
 

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