- #1

- 916

- 4

Any hints would be appreciated. Thank you.

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter arunma
- Start date

- #1

- 916

- 4

Any hints would be appreciated. Thank you.

- #2

- 6,063

- 1,368

arunma said:

Any hints would be appreciated. Thank you.

Yes raising the indices of the metric is analogous to taking the inverse of a matrix:

[tex](g)_{ab}(g^{-1})^{bc}=g_{ab}g^{bc}=\delta_a{}^c=(I)_a{}^c[/tex]

If your cosmology book says "divide one by each element", your metrics are probably diagonal in the basis used.

- #3

- 916

- 4

- #4

- 6,063

- 1,368

Yes, if the metric has an inverse (i.e., is non-degenerate). This is very easy to check!arunma said:

Share: