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Ionisation Potential

  1. Sep 24, 2010 #1
    1. The problem statement, all variables and given/known data

    Arrange the following in the increasing order of ionisation potential.
    1. N,F,O
    2. C,O,N
    3. Au,Cu,Ag

    2. Relevant equations

    Electronic Configurations

    3. The attempt at a solution

    1. The highest ionisation energy will be that of F. Next will be of O because of paired p electrons. Last of N because of 1 unpaired electron.
    So N<O<F
    But answer is O<N<F

    2. On similar reasons, N<C<O
    But again it is C<O<N

    3. Cu<Ag<Au
    Au has f electrons which cause poor shielding effect and hence greater nuclear pull.
    Ag has 4d electrons and Cu has 3d electrons out of which 4d offer weaker screening effect.
    Hence the above order.
    But answer is Ag<Cu<Au

    Please provide detailed explanation
  2. jcsd
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