# Ionization energy

1. Jul 9, 2016

### Magnetic Boy

1. The problem statement, all variables and given/known data.
Suppose the energy difference between the states n=2 and n=3 is E(eV), in an hydrogen atom. then the ionization potential in volts is: A) 13.2E B) 7.2E C) 3.2 E D) 0.56E

2. Relevant equations
En = -13.7 × Z^2÷n^2

3. The attempt at a solution
I just know the ionization energy is equal to the total energy in last stationary state. but i cant apply the concept on this problem.

2. Jul 9, 2016

### malawi_glenn

E = (-13.7)/9-(-13.7)/4 is the energy difference

And the ionization energy is 13.7eV

what do you think you have to do now?

3. Jul 9, 2016

### Joyal Babu

You got the energy in each state.Divide that by 1.60218e-19 you get the ionization potential of each state in eV.Now find the difference between n=2 and n=3 states.Give that as E.Find ionization potential in n=1.See what multiple of E is that.You got the answer.They gave "ionization potential in volts" to confuse you.
Volt*Q(e)=eV.In this problem both have the same numerical value.

4. Jul 9, 2016

### Magnetic Boy

Thank you. It was helpful. And solved.