- #1

cooper1

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## Homework Statement

Given an iron bar, of round cross-section, fixed by its extremities

(bar measures 152 mm in length and 4.8 mm in diameter),

a weight of 88.5 kgs is hung from its middle, bending it at least

90 degrees.

How much weight/force would be needed to bend another

bar of the same material and size, but of hexagonal or square

section?

## Homework Equations

Torque = Force * R

Sin(90°) * R

## The Attempt at a Solution

Haven't got any idea. There should

be something lacking in the text or

more probably some calculus skills

given as knows and hence omitted.

Hope you could clear up this question,

thank you in advance