# Irrational Numbers

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shmoe
Homework Helper

"You do not have the permission to view this blog"

I guess you have to register to see it?

Can you type the problem here?

you should be able to see it now. changed the settings

shmoe
Homework Helper
I'm getting a page that says it's your blog, but it also says "total entries: 0" and there's not much tehre besides a calender.

Is it that long of a problem that you couldn't just type it in here?

yeah, now it should work.

Last edited:
StatusX
Homework Helper
shmoe
Homework Helper
Alright. You get to p^2=n*q^2 and then assume that n=2*t? That's completely unjustified.

If n is not a perfect square then you can write it as n=r*m^2 where r has the property that if s is a prime and s divides r then s^2 does not divide r, r>1 obviously as well (you should prove this). Proceed from p^2=n*q^2 and see what happens.

You could also just look at the prime factorization of n if you have unique factorization at this point.

Ok, so $$p^{2} = rm^{2}q^{2}$$ and $$p^{2}$$ is divisible by $$rm^{2}$$. So then I have to show that $$q^{2}$$ is also divisible by $$rm^{2}$$. Is $$m$$ just any positive number?

Thanks

shmoe
Ok, so $$p^{2} = rm^{2}q^{2}$$ and $$p^{2}$$ is divisible by $$rm^{2}$$. So then I have to show that $$q^{2}$$ is also divisible by $$rm^{2}$$. Is $$m$$ just any positive number?